3x^2-1,2x=0

Solution for 3x^2-1,2x=0 equation:

3x^2-1.2x=0

a = 3; b = -1.2; c = 0;
Δ = b2-4ac
Δ = -1.22-4·3·0
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{1.44}}{2*3}=\frac{1.2-\sqrt{1.44}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{1.44}}{2*3}=\frac{1.2+\sqrt{1.44}}{6}
$